在弄一个php扩展, 想把 扩展写成类的 形式, 于是在声明的时候 想给类加个array 属性
于是expect 代码是这样的

PHP_MINIT_FUNCTION(concurrency)
{
	zend_class_entry ce;
	INIT_CLASS_ENTRY(ce, PHP_CONCURRENCY_CLASSNAME, concurrency_class_methods);
	concurrency_class_entry = zend_register_internal_class(&ce TSRMLS_CC);

	zval *requests;

	MAKE_STD_ZVAL(requests);

	array_init(requests);

	zend_printf("%d", requests->type);
	zend_declare_property(concurrency_class_entry, "requests", strlen("requests"), requests, ZEND_ACC_PUBLIC);

	return SUCCESS;
}

结果报错,
PHP Fatal error: Internal zval’s can’t be arrays, objects or resources in Unknown on line 0
把requests->type 用zend_printf打出来发现 结果是4 是 ZEND定义的IS_ARRAY,
继续翻代码
发现在Zend/zend_API.c 里面zend_declare_property的原型 有这样的定义

if (ce->type & ZEND_INTERNAL_CLASS) {
		switch(Z_TYPE_P(property)) {
			case IS_ARRAY:
			case IS_CONSTANT_ARRAY:
			case IS_OBJECT:
			case IS_RESOURCE:
				zend_error(E_CORE_ERROR, "Internal zval's can't be arrays, objects or resources");
				break;
			default:
				break;
		}
	}

不知何意看
staceflow 上也有人遇到这种问题
http://stackoverflow.com/posts/1105360/revisions
,没办法,
于是就改成在构造函数里面 增加属性的声明
just as follow

PHP_METHOD(Concurrency, __construct)
{
	zval *pThis;
	pThis = getThis();
	
	zval *requests;
	MAKE_STD_ZVAL(requests);
	array_init(requests);

	add_property_zval_ex(pThis, "requests", sizeof("requests"), requests);
}

在这里记下!